Computing...

Input information:

photon energy |  \nwavelength | 435 nm  (nanometers)


Result:

energy | 4.567×10^-19 J  (joules)\n= 2.85 eV  (electronvolts)\n= 4.328×10^-22 BTU_IT  (IT British thermal units)


Equation:

E = (h c)\/lambda |  \nE | energy\nlambda | wavelength\nh | Planck constant (~~ 6.62607×10^-34 J s)\nc | speed of light (~~ 2.998×10^8 m\/s)

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