Wolfram|Alpha

Computing...

Input information:

mechanical stress for a cylinder |  \ndiameter | 5 mm  (millimeters)\nforce | 2 N  (newtons)


Result:

mechanical stress | 101.9 kPa  (kilopascals)\n= 14.77 psi  (pounds-force per square inch)\n= 0.1019 MPa  (megapascals)


Equation:

sigma = F\/(pi (d\/2)^2) |  \nsigma | mechanical stress\nd | diameter\nF | force


Schematic: